Largest product in a series : Problem 8 Euler Project

Largest product in a series : Problem 8

The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?

Don't forget to save the series in a text file named  "8.txt" in the working directory
Problem Source : Euler Project

Python Code:

def largestProduct():
    largestP = 1
    stringNumb = ""
    f = open('8.txt','r')
    for line in f:
        t = line[0:len(line)-1]
        stringNumb = stringNumb + str(t)
    print len(stringNumb)   
    for i in range(1000-13+1):
        temp = 1
        k = i
        for j in range(13):
            temp = temp*(int(stringNumb[k]))
            k = k + 1
        if temp> largestP:
            largestP = temp
        i = i+1       
               
    print "Largest Product in the Series",largestP           
largestProduct()