Banking ICSE Interest Calculator

Calculation of interest on a savings bank account

Mini Python project for middle and high school students

Example

Run the code on google colaboratory

Python Code:

class Solution(object):

    def Banking(self, numberOfMonths):

        transactions = dict()

        for i in range(numberOfMonths):

            month = str(input("Enter the month:"))

            transactions_for_month = int(

                input("Enter the number of transactions for this month:"))

            tempList = []

            for j in range(transactions_for_month):

                tempList.append(int(input("Enter the date of the month:")))

                # put a negative sign before the number if the amount is withdrawn

                tempList.append(

                    float(input("Enter the amount deposited or withdrawn:")))

            transactions[month] = tempList

        #print(transactions)

        self.MinimumBalance(transactions)

    def MinimumBalance(self, transactions):

        key = list(transactions.keys())

        balance = []

        balanceFinal = 0

        date = []

        monthWiseMBList = []

        for i in range(len(transactions)):

            for j in range(len(transactions[key[i]])):

                if j % 2 == 0:

                    date.append(transactions[key[i]][j])

                else:

                    balanceFinal += (transactions[key[i]][j])

                    balance.append(balanceFinal)

            balanceFinal = balance[-1]

            #print(balance)

            #print(date)

            if i != 0:

                move_date += int((len(transactions[key[i - 1]]) / 2))

            else:

                move_date = 0

            #print(move_date)

            minimumBalanceMonthly = float('inf')

            flagTransactionLessThanTenth = False

           

            for k in range(len(date) - move_date):

                if date[k+move_date] <= 10:

                    minimumBalanceMonthly = balance[k + move_date]

                    flagTransactionLessThanTenth = True

                else:

                    if minimumBalanceMonthly > balance[k + move_date]:

                        minimumBalanceMonthly = balance[k + move_date]

            if len(transactions[key[i]]) == 0:

                monthWiseMBList.append(monthWiseMBList[i - 1])

            else:

                monthWiseMBList.append(minimumBalanceMonthly)

            if flagTransactionLessThanTenth == False:

                if i == 0:

                    print(monthWiseMBList[i], i, minimumBalanceMonthly)

                    monthWiseMBList[i] = 0

                if i!=0:

                    if monthWiseMBList[i] > monthWiseMBList[i - 1] and len(transactions[key[i]]) != 0:

                        monthWiseMBList[i] = monthWiseMBList[i - 1]

                    else:

                        monthWiseMBList[i] = balance[-1]

            if i == len(key) - 1:

                print("Press Y/y is the account was closed in the month of ", key[-1])

                choice = str(input())

                if choice == "Y" or choice == "y":

                    monthWiseMBList[-1] = 0

            print("Minimum Monthly Balance for the month of ", key[i], "= ",

                  monthWiseMBList[i])

        #calculation of interest

        qualifyingAmount = 0

        for j in (monthWiseMBList):

            qualifyingAmount += j

        print("Total of balances ", qualifyingAmount)

        rate_of_interest = float(input("Enter the rate of interest:"))

        interest = (qualifyingAmount * rate_of_interest * (1 / 12)) / 100.0

        print("Total interest earned = ", round(interest, 2))

obj = Solution()

numberOfmonths = int(input("Enter the number of months:"))

obj.Banking(numberOfmonths)

Leet Code Rotate Image

Leet Code Rotate Image 

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]

Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

 

Constraints:

• n == matrix.length == matrix[i].length
• 1 <= n <= 20
• -1000 <= matrix[i][j] <= 1000

class Solution:

    def rotate(self, matrix):

        order = len(matrix[0])

        newmatrix = []

        for i in range(order):

            newmatrix.append([])

            for j in range(order):

                newmatrix[i].append(0)

        newColoumn = []

        for i in range(order):

            newColoumn.append(order-1-i)

        for i in range(order):

            for j in range(order):

                newmatrix[j][newColoumn[i]] = matrix[i][j]

        for i in range(order):

            for j in range(order):

                matrix[i][j] = int(newmatrix[i][j])

        print(matrix)

obj = Solution()

#change the matrix here

matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]

obj.rotate(matrix)

Leet Code Longest Substring Without Repeating Characters

Given a string s, find the length of the longest 

substring

 without repeating characters.

 

Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.

Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

Example 3:

Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.

 

Constraints:

• 0 <= s.length <= 5 * 104
• s consists of English letters, digits, symbols and spaces.

class Solution:

    def lengthOfLongestSubstring(self, s: str) -> int:

        maxLength = 0

        for i in range(len(s)):

            substring = []

            for j in range(i,len(s)):

                if s[j] in substring:

                    break

                else:

                    substring.append(s[j])

            if len(substring) > maxLength:

                maxLength = len(substring)

        return maxLength

obj = Solution()

s = str(input("Enter a string:"))

print(obj.lengthOfLongestSubstring(s))

Leet Code ZigZag Conversion

 

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

 

Example 1:

Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"

Example 2:

Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P     I    N
A   L S  I G
Y A   H R
P     I

Example 3:

Input: s = "A", numRows = 1
Output: "A"

 

Constraints:

• 1 <= s.length <= 1000
• s consists of English letters (lower-case and upper-case), ',' and '.'.
• 1 <= numRows <= 1000

import numpy as np

class Solution(object):

    def convert(self, s, numRows):

        numCols = len(s)

        arr_characters = np.zeros(numRows * numCols).reshape(numRows, numCols)

        #print(arr_characters)

        if numRows == 1:

            return s

        else:

            counter = 0

            pos = 0

            vertical_shift = 0

            for i in range(len(s)):

                if counter <= numRows:

                    _zero = 0

                    for j in range(numRows):

                        if pos >= len(s):

                            break

                        else:

                            #print(s[pos],end=' ')

                            #print("(",_zero,vertical_shift,")",end= ' ') # = ord(s[pos])

                            arr_characters[_zero][vertical_shift] = ord(s[pos])

                            pos += 1

                            _zero += 1

                    counter = numRows + 1

                    vertical_shift += (numRows - 1)

                    #print(vertical_shift,"***************")

                else:

                    diagonal_shift_col = vertical_shift - (numRows - 2)

                    diagonal_shift_row = numRows - 2

                    for j in range(numRows - 2):

                        if pos >= len(s):

                            break

                        else:

                            #print(s[pos],end = ' ')

                            #print("(",diagonal_shift_row,diagonal_shift_col,")",end= ' ') # = ord(s[pos])

                            arr_characters[diagonal_shift_row][diagonal_shift_col] = ord(s[pos])

                            diagonal_shift_col += 1

                            diagonal_shift_row -= 1

                            pos += 1

                    #print("**************")

                    counter = 0

            #print(arr_characters)

            output = ""

            for i in range(numRows):

                for j in range(numCols):

                    if arr_characters[i][j] != 0:

                        output += chr(int(arr_characters[i][j]))

                    else:

                        output += ""

            #output.encode('utf-8')

            return output

obj = Solution()

s = ""

numRows = int(input("Enter the number of rows:"))

s = str(input("Enter the string:"))

print(obj.convert(s, numRows))