Question 2:
Write a program to declare a matrix A[][]of order ( M*N) where 'M' is the number of rows
and 'N' is the number of columns such that the value of "M' must be greater than 0 and
less than 10 and the value of 'N' must be greater than 2 and less than 6. Allow the
user to input digits (0-7) only at each location, such that each row represents an octal
number.
Example:
231(decimal equivalent of 1st row=153 i.e. 2*8² +3*8¹ +1*8⁰)
405(decimal equivalent of 1st row=261 i.e.4*8¹+0*8¹+5*8⁰ )
156(decimal equivalent of 1st row=110 i.e. 1*8²+5*8¹+6*8⁰)
Perform the following tasks on the matrix:
Display the original matrix.
Calculate the decimal equivalent for each row and display as per
the format given below.
Example 1:
Input:
ENTER ROW SIZE M=3
ENTER COLUMN SIZE
N=4
ENTER ELEMENTS FOR ROW 1: 1 1 3 7
ENTER ELEMENTS FOR ROW 2: 2 1 0 6
ENTER ELEMENTS FOR ROW 3: 0 2 4 5
Output:
FILLED MATRIX DECIMAL EQUIVALENT
1 1 3 7 607
2 1 0 6 1094
0 2 4 5 165
Example 2:
Input:
ENTER ROW SIZE M=3
ENTER COLUMN SIZE N=3
ENTER ELEMENTS FOR ROW 1: 0 2 8
Output:
INVALID INPUT
Example 3:
Input:
ENTER ROW SIZE M=3
ENTER COLUMN SIZE N=9
Output:OUT OF RANGE
import java.util.*;
public class
ISC2020Q2 {
public
static void main(String[] args) {
int M,N;
System.out.println("Input:");
Scanner in = new
Scanner(System.in);
do {
System.out.println("ENTER ROW SIZE:");
M = in.nextInt();
System.out.println("ENTER COLUMN SIZE:");
N = in.nextInt();
if(M<0 || M>9 || N <3 || N > 5)
System.out.println("OUT OF RANGE, TRY AGAIN:");
}while(M<0 || M>9 || N <3 || N > 5);
Matrix obj = new Matrix(M,N);
obj.inputElements();
System.out.println("Filled Matrix Decimal Equivalent");
obj.display();
in.close();
}
}
class Matrix {
private
void convertsRowToOctalEquivalent() {
int temp;
for(int i=0;i<M;i++) {
rowOctalEquivalent[i]=0;
temp=N-1;
for(int j=0;j<N;j++) {
rowOctalEquivalent[i] += mat[i][j]*(int)Math.pow(8,temp);
temp--;
}
}
}
public
void display() {
for(int p=0;p<M;p++)
for(int q=0;q<N;q++)
if(MAX_MATRIX
< mat[p][q])
MAX_MATRIX = mat[p][q];
String s,element;
s=Integer.toString(MAX_MATRIX);
for(int i=0;i<M;i++) {
for(int j=0;j<N;j++) {
element=Integer.toString(mat[i][j]); // for formatted output
int tmp=element.length();
while(tmp !=s.length()) {
element +=" ";
tmp++;
}
System.out.print(element+" ");
}
System.out.print("
"+rowOctalEquivalent[i]);
System.out.println();
}
}
public
void inputElements() {
Scanner in = new
Scanner(System.in);
System.out.println("Enter the values of the matrix:");
for(int i=0;i<M;i++) {
System.out.println("Enter the elements of row :"+(i+1));
for(int j=0;j<N;j++) {
mat[i][j]=in.nextInt();
if(mat[i][j]<0 || mat[i][j] > 7) {
System.out.println("Invalid
input,try again:");
j--; // Or you can simply break, as asked in the question
}
}
}
in.close();
convertsRowToOctalEquivalent(); // Calculating the octal equivalent for each row
}
Matrix(int M, int N){
this.M = M;
this.N = N;
mat = new int[M][N];
rowOctalEquivalent
= new int[M];
MAX_MATRIX
=0;
}
private
int[][] mat;
private
int M,N;
private
int MAX_MATRIX;
private
int[] rowOctalEquivalent;
}
