Self powers : Problem 48 Euler Project

Self powers : Problem 48 Euler Project

The series, 1¹ + 2² + 3³ + ... + 10¹⁰ = 10405071317.
Find the last ten digits of the series, 1¹ + 2² + 3³ + ... + 1000¹⁰⁰⁰.

Python Code

def selfPower():
     sumT = 0
     for i in range(1000):
             i = i+1
             sumT = sumT + (i**i)%10000000000
     print "last ten digits of the sum:",sumT%10000000000
selfPower()